VCE JS-Dev-101 Dumps, JS-Dev-101 Valid Cram Materials
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Salesforce JS-Dev-101 Exam Syllabus Topics:
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Salesforce JS-Dev-101 Valid Cram Materials & JS-Dev-101 Study Test
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Salesforce Certified JavaScript Developer - Multiple Choice Sample Questions (Q114-Q119):
NEW QUESTION # 114
A developer publishes a new version of a package with bug fixes but no breaking changes. The old version number was 2.1.1.
What should the new package version number be based on semantic versioning?
- A. 3.1.1
- B. 2.2.0
- C. 2.2.1
- D. 2.1.2
Answer: D
Explanation:
Semantic versioning: MAJOR.MINOR.PATCH
MAJOR: incompatible API changes.
MINOR: add functionality in a backward compatible manner.
PATCH: backward compatible bug fixes.
Here:
Bug fixes only, no breaking changes → increment PATCH.
From 2.1.1 to 2.1.2.
So the correct new version is 2.1.2.
________________________________________
NEW QUESTION # 115
Which two console logs outputs NaN ?
Choose 2 answers
- A. console.log(10/ Number('5'));
- B. console.log(parseInt('two'));
- C. console.log(10/ ''five);
- D. console.log(10/0);
Answer: B,C
NEW QUESTION # 116
Refer to the following code block:
01 let array = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11];
02 let output = 0;
03
04 for (let num of array) {
05 if (output > 10) {
06 break;
07 }
08 if (num % 2 == 0) {
09 continue;
10 }
11 output += num;
12 }
What is the value of output after the code executes?
- A. 0
- B. 1
- C. 2
- D. 3
Answer: D
Explanation:
Comprehensive and Detailed Explanation From Exact Extract JavaScript knowledge:
This code uses:
A for...of loop to iterate over values in array.
break to exit the loop entirely when output > 10.
continue to skip even numbers.
It sums only certain numbers into output.
Let's walk through the loop step by step.
Initial values:
array = [1,2,3,4,5,6,7,8,9,10,11]
output = 0
Loop: for (let num of array) { ... }
First iteration: num = 1
Line 05: if (output > 10) → 0 > 10 is false → no break.
Line 08: if (num % 2 == 0) → 1 % 2 == 1, not 0, so false → no continue.
Line 11: output += num → output = 0 + 1 = 1.
Second iteration: num = 2
output > 10 → 1 > 10 is false → no break.
num % 2 == 0 → 2 % 2 == 0, so true → continue.
Because of continue, line 11 is skipped.
output remains 1.
Third iteration: num = 3
output > 10 → 1 > 10 is false.
num % 2 == 0 → 3 % 2 == 1, false → no continue.
output += num → output = 1 + 3 = 4.
Fourth iteration: num = 4
output > 10 → 4 > 10 is false.
num % 2 == 0 → 4 % 2 == 0, true → continue.
Skip sum; output remains 4.
Fifth iteration: num = 5
output > 10 → 4 > 10 is false.
num % 2 == 0 → 5 % 2 == 1, false.
output += num → output = 4 + 5 = 9.
Sixth iteration: num = 6
output > 10 → 9 > 10 is false.
num % 2 == 0 → 6 % 2 == 0, true → continue.
output remains 9.
Seventh iteration: num = 7
output > 10 → 9 > 10 is false.
num % 2 == 0 → 7 % 2 == 1, false.
output += num → output = 9 + 7 = 16.
Eighth iteration would be num = 8, but:
At the top of the loop body, line 05 is checked again:
if (output > 10) → 16 > 10 is true, so break; is executed.
When break runs:
The loop terminates immediately.
No further iterations (for num = 8, 9, 10, 11) are executed.
Therefore, output stays at 16.
Final value of output after the loop ends is 16.
This matches option A.
Why other options do not match:
B . 25: Would require adding more odd numbers (e.g., 9, 11) after 7, but the loop stops early due to output > 10.
C . 11: Would be smaller; the actual sum of 1 + 3 + 5 + 7 until break is 16.
D . 36: Would require summing many more values (e.g., most or all odd numbers up to 11), but again, the break condition stops the loop once output exceeds 10.
So:
Answe r: A
JavaScript knowledge / Study Guide references (concept names only, no links):
for...of loop over arrays
break statement in loops (terminating a loop early)
continue statement in loops (skipping to the next iteration)
Modulo operator % to test even and odd numbers
Step-by-step execution and control flow in loops
NEW QUESTION # 117
A developer at Universal Containers is creating their new landing page based on HTML, CSS, and JavaScript.
To ensure that visitors have a good experience, a script named personalizeWebsiteContent needs to be executed when the webpage is fully loaded (HTML content and all related files), in order to do some custom initializations.
Which implementation should be used to call Fe:s:-a;::eHec5;te::.-.ter.: based on the business requirement above?
- A. Add a listener to thewindow object to handle the DOMContentLoaded event
- B. Add a listener to the window object to handle the lead event
- C. Add a handler to the personalizeWebsiteContent script tohandle the DOMContentLoaded event
- D. Add a handler to the personalizeWebsiteContent script to handle the load event
Answer: B
NEW QUESTION # 118
A developer initiates a server with the file server.js and adds dependencies in the source code's package.json that are required to run the server.
Which command should the developer run to start the server locally?
- A. node start
- B. npm start
- C. start server.js
- D. npm start server.js
Answer: B
Explanation:
Comprehensive and Detailed Explanation From JavaScript/Node.js Knowledge:
In a Node.js project that uses package.json, you typically define a "start" script:
{
"scripts": {
"start": "node server.js"
}
}
Then you start the app with:
npm start
npm start:
Looks up the "start" script in package.json.
Runs the command defined there (commonly node server.js).
This is the standard way to start a Node.js app with npm-managed dependencies.
Why others are incorrect:
A . node start
Tries to run a file named start with Node; does not use package.json scripts.
C . npm start server.js
npm start does not take the script filename as an argument in this way; it just runs the start script as defined.
D . start server.js
Not an npm or node command; on some shells it just tries to "start" a process but is not the standard Node/npm workflow.
Relevant concepts: package.json, npm scripts, npm start, Node entry file execution.
________________________________________
NEW QUESTION # 119
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